A module with an MTTF of 50 years for all failure modes has what total failure rate for all failure modes?

A module with an MTTF of 50 years for all failure modes has what total failure rate for all failure modes?

• A. 0.02 failures per year
• B. 50 failures per year
• C. 0.00002 failures per hour
• D. 0.01 failures per year

Answer: (A)

To determine the total failure rate for all failure modes based on the Mean Time To Failure (MTTF), you can use the relationship between MTTF and failure rate. The failure rate (λ) can be calculated using the formula: λ = 1 / MTTF. Given that the MTTF is 50 years, you can substitute this value into the formula: λ = 1 / 50 years = 0.02 failures per year. This means that, on average, the module experiences 0.02 failures in one year for all failure modes combined. This calculation supports the conclusion that the total failure rate for all failure modes is indeed 0.02 failures per year, making it the correct answer. Based on this understanding, the other options do not align with the calculations derived from MTTF. For instance, a failure rate of 50 failures per year implies a much shorter MTTF, which conflicts with the provided MTTF of 50 years. Similarly, the rate of 0.00002 failures per hour and 0.01 failures per year do not correspond with the given MTTF either, as they represent different values when converted to a yearly basis.

To determine the total failure rate for all failure modes based on the Mean Time To Failure (MTTF), you can use the relationship between MTTF and failure rate. The failure rate (λ) can be calculated using the formula:

λ = 1 / MTTF.

Given that the MTTF is 50 years, you can substitute this value into the formula:

λ = 1 / 50 years = 0.02 failures per year.

This means that, on average, the module experiences 0.02 failures in one year for all failure modes combined. This calculation supports the conclusion that the total failure rate for all failure modes is indeed 0.02 failures per year, making it the correct answer.

Based on this understanding, the other options do not align with the calculations derived from MTTF. For instance, a failure rate of 50 failures per year implies a much shorter MTTF, which conflicts with the provided MTTF of 50 years. Similarly, the rate of 0.00002 failures per hour and 0.01 failures per year do not correspond with the given MTTF either, as they represent different values when converted to a yearly basis.